10c^2+39c-27=0

Solution for 10c^2+39c-27=0 equation:

Simplifying
10c2 + 39c + -27 = 0

Reorder the terms:
-27 + 39c + 10c2 = 0

Solving
-27 + 39c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-9 + -2c)(3 + -5c) = 0

Subproblem 1
Set the factor '(-9 + -2c)' equal to zero and attempt to solve:

Simplifying
-9 + -2c = 0

Solving
-9 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + -2c = 0 + 9

Combine like terms: -9 + 9 = 0
0 + -2c = 0 + 9
-2c = 0 + 9

Combine like terms: 0 + 9 = 9
-2c = 9

Divide each side by '-2'.
c = -4.5

Simplifying
c = -4.5
Subproblem 2
Set the factor '(3 + -5c)' equal to zero and attempt to solve:

Simplifying
3 + -5c = 0

Solving
3 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -5c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -5c = 0 + -3
-5c = 0 + -3

Combine like terms: 0 + -3 = -3
-5c = -3

Divide each side by '-5'.
c = 0.6

Simplifying
c = 0.6
Solution
c = {-4.5, 0.6}